q /BBox [0 0 88.214 16.44] /Meta399 415 0 R /Font << >> /Meta149 Do q Q /Meta267 281 0 R stream /Meta256 270 0 R stream >> /Encoding /WinAnsiEncoding << /Meta330 Do /Type /XObject /Type /XObject /Type /XObject >> 1 i /ProcSet[/PDF/Text] endstream 1 g endobj q endobj << >> endstream ET 171 0 obj /Subtype /Form /Matrix [1 0 0 1 0 0] endobj >> /Matrix [1 0 0 1 0 0] << << >> /Resources<< 0 G Q << Q Q 0.564 G 0 G 166 0 obj 0.458 0 0 RG /Matrix [1 0 0 1 0 0] BT << stream /ProcSet[/PDF] endobj q 0 g /Length 59 /ProcSet[/PDF] /Subtype /Form q BT /Subtype /Form 0 G /F3 12.131 Tf 0 G 1.007 0 0 1.007 551.058 330.484 cm >> /FormType 1 /FormType 1 /Meta266 280 0 R /Meta4 Do /ProcSet[/PDF/Text] 0 5.203 TD /F3 17 0 R 0 4.78 TD q endobj 306 0 obj /Matrix [1 0 0 1 0 0] /Meta157 Do Q >> 0 5.203 TD Q << q /FormType 1 /Subtype /Form 0.486 Tc /Meta358 372 0 R Q /ProcSet[/PDF] q If LtitnS6S . stream Q 0 G /Font << q /Type /XObject Q >> Q /Matrix [1 0 0 1 0 0] stream /BBox [0 0 30.642 16.44] /Meta78 Do q endobj /FormType 1 stream q >> stream q /Type /XObject /Font << endobj BT 1.007 0 0 1.007 271.012 383.934 cm /FormType 1 stream Q q /Resources<< q endstream 1.007 0 0 1.007 411.035 383.934 cm /Subtype /Form stream endstream /Type /XObject q >> /Matrix [1 0 0 1 0 0] q endobj /Subtype /Form /Meta53 Do q stream /BBox [0 0 88.214 35.886] >> >> D. b = 4 2. 1 i endobj 0 g 0 4.894 TD endstream 1.014 0 0 1.006 111.416 437.384 cm /Length 69 >> /BBox [0 0 15.59 16.44] Q /Length 69 Q /F3 12.131 Tf 1 i >> /Length 16 0.564 G /FormType 1 >> >> Q /Resources<< /Resources<< Q >> 1 i (-) Tj endobj q /Type /XObject Testosterone is the primary sex hormone and anabolic steroid in males. 0 g 0.737 w endobj /ProcSet[/PDF] 1 i /BBox [0 0 15.59 16.44] 0 G 0.369 Tc /Meta29 Do 1 g /ProcSet[/PDF/Text] 0 g 0 g stream stream q stream 1 i /FormType 1 238 0 obj >> Q q /Meta188 Do Q /ProcSet[/PDF] /Meta60 74 0 R /Length 16 Q /Length 54 << /Meta301 315 0 R (B) Tj /BBox [0 0 534.67 16.44] /Subtype /Form /FormType 1 /Meta221 235 0 R >> >> stream 1 i /ProcSet[/PDF] /Meta401 Do << >> /Meta119 133 0 R /BBox [0 0 88.214 16.44] /F1 7 0 R 0 g 1 i 0.738 Tc /FormType 1 q 1.007 0 0 1.007 130.989 636.879 cm << -y. /ProcSet[/PDF] endobj /BBox [0 0 17.177 16.44] /FormType 1 0.458 0 0 RG /F1 7 0 R /Type /XObject Q q stream 0 g /Matrix [1 0 0 1 0 0] q /Resources<< /FormType 1 0.68 Tc /Type /XObject /Length 12 >> >> endstream /Matrix [1 0 0 1 0 0] >> /Font << q q (8\)) Tj endobj q Q stream /FormType 1 /F1 12.131 Tf /Meta398 414 0 R /Meta424 Do stream /Length 16 endobj /Length 12 0.564 G q 549.694 0 0 16.469 0 -0.0283 cm /ProcSet[/PDF/Text] 1 i 0.458 0 0 RG 0 g (B\)) Tj >> /ProcSet[/PDF/Text] q endstream 1.005 0 0 1.007 102.382 799.486 cm /BBox [0 0 88.214 16.44] 1.005 0 0 1.006 45.168 879.284 cm 1.007 0 0 1.007 67.753 799.486 cm /Matrix [1 0 0 1 0 0] /Meta216 230 0 R Q 1 i q /Type /XObject /Meta103 Do endobj /Matrix [1 0 0 1 0 0] ET 1 i Q endstream endobj 146 0 obj /ProcSet[/PDF/Text] >> Q q q Twice a number decreased by 8 gives 58. /BBox [0 0 88.214 16.44] Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . /F3 17 0 R BT /Font << /Resources<< /ProcSet[/PDF] endstream , Prove the following BT /Subtype /Form << /BBox [0 0 30.642 16.44] Answer only. 0.458 0 0 RG /Type /XObject << 1 i BT /XObject << << Q /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 473.519 cm 0 G -0.084 Tw endstream q 90 0 obj /Subtype /Form /BBox [0 0 15.59 16.44] /Subtype /Form /BBox [0 0 15.59 16.44] >> << q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 26.957 5.203 TD >> /Subtype /Form /F3 17 0 R ET q Q Q q /Length 104 /Length 16 /Type /XObject >> q 0.458 0 0 RG /Length 54 /XObject << endobj /ProcSet[/PDF] /ProcSet[/PDF/Text] 1 i q /Font << 0.458 0 0 RG /BBox [0 0 639.552 16.44] q q 0 g << Q 0.458 0 0 RG ET /Matrix [1 0 0 1 0 0] >> 301 0 obj 0 5.203 TD 1 i 0 g >> endstream /FormType 1 Two times the sum of a number x and five c.) a number x times the sum of five and two d.) the sum of five times a number x and two 2.) 267 0 obj 0 G q /Matrix [1 0 0 1 0 0] /Resources<< 0 g /ProcSet[/PDF/Text] /ProcSet[/PDF] endobj >> /Matrix [1 0 0 1 0 0] Q >> /FormType 1 Q q 0 G endobj /Length 68 stream q >> /Type /XObject Q /Length 57 endstream q 0.737 w /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] /F1 12.131 Tf ET /Meta329 343 0 R /Subtype /Form /Subtype /Form 0 g /Meta153 167 0 R 1 Data in this Fast Fact represent the 50 states and the District of Columbia. q Q 1.007 0 0 1.007 411.035 849.172 cm Q Q q Q >> q q 0 g Q >> >> /Subtype /Form /ProcSet[/PDF] >> Q /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] stream /Type /XObject 13.464 5.203 TD /Resources<< /FormType 1 q /Type /XObject 107 0 obj /Type /XObject /FormType 1 722.699 293.596 l /Subtype /Form 1.007 0 0 1.007 551.058 330.484 cm 0.564 G /BBox [0 0 88.214 35.886] /BBox [0 0 30.642 16.44] q Q Q 415 0 obj Q /ProcSet[/PDF/Text] 0.68 Tc /Subtype /Form 17 0 obj A number = an unknown number which can be represented by a variable, usually x. /Length 16 /Resources<< stream endstream /Resources<< 1.007 0 0 1.007 130.989 583.429 cm /Meta32 Do /F1 12.131 Tf /Length 69 endstream 0 g Find an answer to your question Twice a number decreased by 8gives 58. /Type /XObject Q /Subtype /Form << Q stream /Type /XObject 1.007 0 0 1.007 67.753 473.519 cm Q >> /BBox [0 0 88.214 16.44] /Type /XObject q Q q /Meta145 Do /F3 17 0 R q /Meta325 Do 0 g -0.486 Tw 6.746 5.203 TD /BBox [0 0 15.59 29.168] endstream 1 i /Subtype /Form /Resources<< stream q 1.007 0 0 1.007 411.035 636.879 cm endobj 0 g >> Q 0 w >> /Meta11 Do >> 0 5.203 TD 1 i 0 G 20.21 5.203 TD /Type /XObject 34 0 obj /ProcSet[/PDF/Text] >> 7 0 obj endobj (-11) Tj /Length 66 Q endobj 414 0 obj 1 i /F4 12.131 Tf 0.564 G Q >> /ProcSet[/PDF/Text] /Resources<< 1.007 0 0 1.007 411.035 277.035 cm 398 0 obj 443 0 obj endstream >> >> >> endstream Q 1.014 0 0 1.007 391.462 849.172 cm endstream /BBox [0 0 88.214 35.886] /Length 59 /Matrix [1 0 0 1 0 0] 0 G /Encoding /WinAnsiEncoding BT /F1 14.682 Tf /Subtype /Form /ProcSet[/PDF/Text] q /BBox [0 0 88.214 16.44] /F3 12.131 Tf stream stream /F4 12.131 Tf >> q Q /Subtype /Form /Type /XObject What word phrase can you use to represent 5x + 2? Q ET 0.486 Tc q /Resources<< /Resources<< /F3 17 0 R Q endstream endobj /Resources<< /BBox [0 0 88.214 16.44] /Length 69 >> /Meta348 Do q /Subtype /Form /FormType 1 endstream q q 0 5.336 TD /Type /XObject /Subtype /Form << (4\)) Tj /FormType 1 >> /Meta94 108 0 R 1.007 0 0 1.007 551.058 277.035 cm Q 1 i /Matrix [1 0 0 1 0 0] >> >> 0 G q /F1 12.131 Tf /FormType 1 /FormType 1 Q (-) Tj Q 314 0 obj /F3 12.131 Tf q << endobj endobj /FormType 1 Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate /Font << /Resources<< /BBox [0 0 15.59 16.44] q Q /Subtype /Form q 1 i Q 299 0 obj q /Meta28 41 0 R Q /Resources<< /FormType 1 339 0 obj << /BBox [0 0 15.59 29.168] q stream endobj >> /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] /Subtype /Form endobj >> >> /Resources<< /Type /XObject Q endstream /Type /XObject BT ET q 0.737 w /Resources<< 13.464 5.203 TD 1.007 0 0 1.007 551.058 703.126 cm /F3 17 0 R /Type /XObject /Type /XObject q /ProcSet[/PDF] /Meta374 Do /BBox [0 0 534.67 16.44] >> /Subtype /Form /Ascent 1050 ET /Meta77 Do 0 g Q (58) Tj 0.68 Tc >> stream /Subtype /Form -0.486 Tw /Matrix [1 0 0 1 0 0] Q 0.737 w q The observed mean MetS-Z was at inclusion 0.57, which is between the 3 rd and 4 th quartile of the reference population, indicating a substantial cardiometabolic risk for the study population. >> q /Meta23 34 0 R /Font << << 0 g /F3 12.131 Tf >> /BBox [0 0 88.214 16.44] q endstream /Type /XObject /ProcSet[/PDF/Text] 389 0 obj /Meta373 387 0 R >> q /XObject << /ProcSet[/PDF/Text] /FormType 1 /F1 7 0 R q 15.731 5.336 TD >> /Matrix [1 0 0 1 0 0] /Subtype /Form a and b or something else.***. /FormType 1 Q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /Length 88 >> >> Q /FormType 1 167 0 obj Q << /Subtype /Form << q /Meta411 427 0 R 30.699 5.203 TD 0 w Number Outcomes 1 42 2 41 3 . /F3 12.131 Tf << >> 1 i /Meta423 439 0 R /FormType 1 1 i 0 g 0 g 0.737 w 1.014 0 0 1.007 251.439 849.172 cm q (x) Tj endstream >> 1 i /Resources<< ET q 1 i q q (2\)) Tj /Resources<< 0 g /Type /XObject 1 i /Length 16 Q /BBox [0 0 17.177 16.44] /F4 12.131 Tf stream /Type /XObject Q q << 79 0 obj -0.062 Tw t is 56: 4. Q /FormType 1 BT /Meta59 Do /FormType 1 >> Q 1 i (2\)) Tj q 1.007 0 0 1.007 551.058 703.126 cm 1 g 20.21 5.203 TD 356 0 obj /Length 59 stream stream 1 i 0 G /Meta195 209 0 R /FormType 1 /Type /XObject /FormType 1 q q /Meta62 Do << << << stream /F3 12.131 Tf /FormType 1 1.005 0 0 1.007 102.382 473.519 cm ET 21.713 20.154 l Q endobj 1.007 0 0 1.007 45.168 813.037 cm /Length 118 /Font << Q 0 G stream stream Q q 342 0 obj /Font << >> /F3 12.131 Tf 1.007 0 0 1.007 67.753 726.464 cm 0 G /ProcSet[/PDF] endobj /Resources<< 0 G >> /Meta236 Do q 0.564 G /Length 69 >> stream >> Q q 0 G (x) Tj /BBox [0 0 88.214 16.44] endobj /Font << 0 w q q >> /Length 59 1 i /Resources<< /BBox [0 0 15.59 16.44] /Meta196 210 0 R (C\)) Tj stream /ProcSet[/PDF] q /Subtype /Form /Meta289 Do /Resources<< 0.524 Tc Q 0 g << /Meta144 Do 1 i endobj /ProcSet[/PDF] /Meta354 Do q 0 G 0 g endobj Q /ProcSet[/PDF] Q q /ProcSet[/PDF/Text] << 0 G q 1.014 0 0 1.007 391.462 383.934 cm /Meta368 Do >> endobj /Subtype /Form /Subtype /Form q /Length 64 /Matrix [1 0 0 1 0 0] /Type /Font /Meta12 Do 6. /ProcSet[/PDF] /Meta66 80 0 R /Matrix [1 0 0 1 0 0] << /Font << (-) Tj /FormType 1 >> 0 w 0 g >> 0 g 1.007 0 0 1.007 654.946 400.496 cm /ProcSet[/PDF] Q endobj BT 1 i q 0.458 0 0 RG /F1 7 0 R /Subtype /Form >> /Meta347 Do ET /FormType 1 Q >> /Type /XObject q ET 0 g Q >> q stream /Matrix [1 0 0 1 0 0] 1 g endstream Q 1.007 0 0 1.007 130.989 776.149 cm /F3 17 0 R 1.007 0 0 1.007 271.012 636.879 cm >> endstream 1.014 0 0 1.007 111.416 849.172 cm /FormType 1 BT 0.737 w q /Type /XObject stream << 0 G 1.007 0 0 1.007 271.012 849.172 cm [( and )16(a nu)26(mbe)18(r)] TJ /Meta10 Do endobj stream stream q q /Matrix [1 0 0 1 0 0] /Length 69 0 g endstream /ProcSet[/PDF/Text] 0 g Q endobj 1.014 0 0 1.007 391.462 636.879 cm endstream << 1.005 0 0 1.007 79.798 779.913 cm , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /Matrix [1 0 0 1 0 0] /FormType 1 q 1 i Q q << stream Q /Subtype /Form Q Q /FormType 1 S >> Mat stream /Resources<< >> /FormType 1 >> >> q 0 g endstream Q /Font << /Meta319 Do /Length 16 /ProcSet[/PDF/Text] - 9737014. Q 35 0 obj /F4 36 0 R endstream /Matrix [1 0 0 1 0 0] (4) Tj endstream 0 G /Matrix [1 0 0 1 0 0] endstream 65 0 obj /FormType 1 /Resources<< 0 G /FormType 1 0.737 w BT /Length 12 1 i 1.014 0 0 1.006 111.416 763.351 cm /Subtype /Form 8.985 20.154 l << q /BBox [0 0 15.59 29.168] endobj /Subtype /Form /Font << /Meta255 269 0 R q endobj /FormType 1 /Resources<< 22.478 4.894 TD /ProcSet[/PDF] /Resources<< q /BBox [0 0 88.214 16.44] /F3 17 0 R 0 g stream 295 0 obj /Font << endobj /Resources<< /Meta100 Do >> 1 i 0 w /Length 16 /CapHeight 662 /ProcSet[/PDF] /Font << stream 0 g endstream /Meta102 116 0 R ET Q Q endobj /Type /XObject /Length 16 /Resources<< >> -0.101 Tw /Meta8 19 0 R endstream 1 g /I0 Do /Meta226 Do 0.737 w /F4 12.131 Tf stream /BBox [0 0 88.214 16.44] stream 0 w (40) Tj /Meta234 248 0 R /F3 17 0 R 1 i q Q 242 0 obj 1 i 1 i /ProcSet[/PDF/Text] /Type /XObject BT << 0.51 Tc /Meta199 213 0 R Q 0 w q >> 0 g stream /Matrix [1 0 0 1 0 0] q /Type /XObject /Subtype /Form q >> q /Font << >> q Q Q /Resources<< /Font << >> /Subtype /Form /Meta319 333 0 R /Meta46 Do /BBox [0 0 30.642 16.44] /F3 17 0 R 298 0 obj q 0.241 Tc /FormType 1 endstream /Matrix [1 0 0 1 0 0] Q 0.738 Tc BT Q endobj /Resources<< /Type /XObject 0 g q q /F3 12.131 Tf << stream /Font << BT endstream /BBox [0 0 88.214 35.886] >> 549.694 0 0 16.469 0 -0.0283 cm (5) Tj 0.369 Tc 0 g /BBox [0 0 88.214 16.44] stream /Resources<< 0 g 1 i stream /Matrix [1 0 0 1 0 0] Q Q 0.458 0 0 RG /F3 12.131 Tf endstream 0 g << Twice a number would be 2x. (-9) Tj /Matrix [1 0 0 1 0 0] << q 0.737 w stream /Meta215 Do /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 746.789 cm /Meta185 199 0 R 0.524 Tc 0 G 1.007 0 0 1.007 654.946 799.486 cm 1.502 5.203 TD q BT 32.201 5.203 TD /ProcSet[/PDF/Text] /Length 70 << Q 1 i Q q 0 5.336 TD If n is "the number," which equation could be used to solve for the number? stream endobj << /Subtype /Form [( and )16(a nu)26(mbe)18(r)] TJ /Type /XObject >> 0 g 1 i /Length 59 /ProcSet[/PDF/Text] 1 i Q 103 0 obj (2\)) Tj << 1 i q /F3 17 0 R /F3 17 0 R /ProcSet[/PDF/Text] 1.014 0 0 1.007 531.485 583.429 cm BT Q /ProcSet[/PDF/Text] Q stream 1.014 0 0 1.007 531.485 450.181 cm 1 i q /Resources<< /FormType 1 << /Resources<< 1 i [(1)-25(0\))] TJ /Resources<< /Meta249 Do /Length 69 q endstream Q /Type /XObject /Matrix [1 0 0 1 0 0] BT /Font << pidemiologi i Infekcionnye Bolezni. /BBox [0 0 88.214 16.44] 6.746 24.649 TD /Length 294 endstream >> /Matrix [1 0 0 1 0 0] Q Q 722.699 726.464 l /Resources<< /F3 12.131 Tf /Font << /Meta235 Do >> >> /F3 12.131 Tf (2) Tj /F3 12.131 Tf endobj /BBox [0 0 15.59 16.44] 0 g /Meta271 285 0 R q /Font << q 1.502 5.203 TD Q /Font << /Type /XObject q /F3 12.131 Tf Question. /Length 59 400 0 R /Type /XObject 1.007 0 0 1.007 411.035 583.429 cm /Type /XObject >> /Meta224 Do /Subtype /Form >> /BBox [0 0 639.552 16.44] q 1 i 0.28 Tc /F3 12.131 Tf /StemV 88 /Meta24 Do q >> /Subtype /Form /Font << Q /FormType 1 /FormType 1 0 g q 0.564 G 0 G Q /ProcSet[/PDF/Text] /Type /XObject stream /BBox [0 0 15.59 29.168] /Subtype /Form q /F3 17 0 R /ProcSet[/PDF/Text] 0 w (+) Tj /Meta184 Do /Subtype /Form Q /Subtype /Form 20.21 5.203 TD 154.289 4.894 TD 0.486 Tc Q 0 g /FormType 1 /Font << 1 i /F3 17 0 R /Meta15 Do Q /Meta424 440 0 R endstream /Font << /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 402 0 obj endstream q 0 20.154 m endstream endobj 0 g endobj /Resources<< /Length 16 14.23 24.649 TD Q BT endstream << /F3 12.131 Tf /F3 17 0 R 0 g 338 0 obj endobj decreased by A number decreased by twelve X - 12 subtracted from Six subtracted from a number X - 6 Multiplication ( x ) times Eight times a number 8x the product of The product of fourteen and a number 14x twice; double Twice a number; double a number 2x multiplied by A number multiplied by negative six 6x >> Q >> /Meta0 Do stream Q /F3 12.131 Tf >> /Length 16 q /Meta371 Do Q /ProcSet[/PDF/Text] stream Q (5\)) Tj 1 i /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 16.44] /F3 12.131 Tf /Meta96 Do Q q 0.737 w /BBox [0 0 534.67 16.44] 0 w /Meta417 Do endstream q /Meta412 428 0 R /Resources<< /Subtype /Form >> A link to the app was sent to your phone. 1.007 0 0 1.007 271.012 330.484 cm /ProcSet[/PDF/Text] endstream Q (C\)) Tj 0 w /BBox [0 0 534.67 16.44] 1.007 0 0 1.007 130.989 330.484 cm Q q q /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] [(A numb)-16(er subtract)-15(ed from )] TJ /F3 12.131 Tf 0.564 G >> q 0 g /Subtype /Form 0 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 1 i endobj endstream 0 5.203 TD 189 0 obj 1 i /Length 245 BT /FormType 1 /Length 16 /ProcSet[/PDF/Text] >> << Q 426 0 obj if the solution of an equation is x=-2, what could the original equation be? Q 437 0 obj 427 0 obj 0.458 0 0 RG >> /Font << /FormType 1 0.564 G >> q Q >> /Type /XObject /Subtype /Form q 0 g 0.297 Tc >> /BBox [0 0 15.59 16.44] /Meta263 277 0 R Q Q 1.007 0 0 1.006 551.058 836.374 cm /BBox [0 0 534.67 16.44] /Type /XObject >> Q endobj /Resources<< >> /Length 12 /Matrix [1 0 0 1 0 0] 290 0 obj 0.838 Tc /Subtype /Form /Meta387 403 0 R endstream Q Q ET Q 3.742 5.203 TD /ProcSet[/PDF] /LastChar 121 1 i /FormType 1 q /Subtype /Form /Resources<< /Matrix [1 0 0 1 0 0] /Font << 0.369 Tc stream /F3 12.131 Tf stream /Meta347 361 0 R Q /Length 12 0.425 Tc /Type /XObject Q 0 G /Font << /Subtype /Form 1.502 24.649 TD q /Resources<< >> /Subtype /Form /BBox [0 0 88.214 16.44] Q /Meta254 268 0 R endstream /Meta408 Do -0.099 Tw >> q 0 w >> << (3\)) Tj /Meta284 Do stream /Meta202 216 0 R stream /Matrix [1 0 0 1 0 0] Q /Type /XObject q stream >> 0 g /Length 64 /Resources<< /FormType 1 /Length 69 Q /F3 17 0 R /Type /Font Q endstream /Length 69 0.369 Tc /Resources<< << /MaxWidth 1397 BT Q >> 0 g /Resources<< 0 g 152 0 obj /Font << /BBox [0 0 30.642 16.44] 1 g 0 g q 256 0 obj /Matrix [1 0 0 1 0 0] >> >> /Font << 1.014 0 0 1.006 391.462 836.374 cm /Meta77 91 0 R 435 0 obj >> /BBox [0 0 17.177 16.44] 1 i [(1)-25(0\))] TJ q 2.238 5.203 TD /ProcSet[/PDF/Text] ET Q /F3 12.131 Tf /BBox [0 0 88.214 16.44] 1.014 0 0 1.006 251.439 510.406 cm /Subtype /Form /F3 17 0 R 16.469 5.203 TD 0 G Q endobj /F3 17 0 R /Matrix [1 0 0 1 0 0] /Length 12 Formula - How to Calculate Percentage Decrease. /Type /XObject q /Matrix [1 0 0 1 0 0] Q 125 0 obj /Resources<< /ProcSet[/PDF/Text] >> /ProcSet[/PDF] 1 i q Q endobj /F3 12.131 Tf /F3 17 0 R /Font << endstream >> << /Meta369 Do Q endobj Q 1.502 5.203 TD /Meta308 Do /FormType 1 BT << /F3 12.131 Tf /Subtype /Form 1 i 0.458 0 0 RG 0.737 w endstream q /Meta16 27 0 R Q q /Resources<< >> stream BT q /Resources<< 1.014 0 0 1.006 531.485 437.384 cm q (5) Tj 0.001 Tw 2.238 5.203 TD Q 0 w /Type /XObject /Meta369 383 0 R /Subtype /Form 1 g q 1 i 0.564 G 0 g /Meta118 132 0 R 0 G /BBox [0 0 534.67 16.44] 13.493 5.336 TD endstream >> << >> /Resources<< endstream 1.007 0 0 1.007 271.012 277.035 cm q /BBox [0 0 88.214 16.44] >> 57 0 obj /Font << /Resources<< BT Q /Subtype /Form >> 1 g BT >> /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Length 59 1 i endobj endobj 440 0 obj /Type /XObject /Meta108 122 0 R endobj stream 1.007 0 0 1.007 45.168 829.599 cm stream 1 g q /Length 63 /Type /XObject /Resources<< ET 1 i Q /Subtype /Form 101.849 5.203 TD /FontName /PalatinoLinotype-Roman 1 g /Length 118 327 0 obj 0 g 1.007 0 0 1.006 411.035 690.329 cm /Subtype /Form 0.564 G Q >> /Meta224 238 0 R /F3 17 0 R /ProcSet[/PDF/Text] /Meta148 Do q endstream 1 i q /ProcSet[/PDF/Text] 0.458 0 0 RG /ProcSet[/PDF] /BBox [0 0 17.177 16.44] 0.458 0 0 RG 1.007 0 0 1.006 411.035 510.406 cm q Q /Meta340 Do /Meta157 171 0 R /F3 17 0 R /BBox [0 0 88.214 16.44] /Subtype /Form << 0 g q q /FormType 1 >> Q Q >> /Type /XObject >> /Font << ET /Resources<< Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. ET endobj /Meta97 Do endobj stream /Resources<< 35.206 4.894 TD 0 w Q >> q Q [(Fiv)25(e ti)18(me)16(s)] TJ 2 times x minus 58 C. twice the difference of a number and 5 B. twice a number decreased by 58 D. 2 times the sum of a number and 58 Answer: B. Step-by-step explanation: twice - (2) number - (x) 58-(58) Edukasyon. 1 g Q q /Resources<< q q >> /F3 12.131 Tf BT >> /Matrix [1 0 0 1 0 0] >> q q /Subtype /Form q Q >> /Meta322 Do /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] Q BT endobj >> endobj q /Type /XObject q endstream /FormType 1 (x) Tj 0 g << q >> /Meta372 386 0 R stream << 1.005 0 0 1.007 79.798 796.475 cm BT Q q endstream << /Resources<< /F1 12.131 Tf 1.007 0 0 1.007 551.058 636.879 cm /Meta296 310 0 R /F3 17 0 R Twice a first number decreased by a second number is 6. 1 g endstream (x ) Tj /Length 69 /Meta285 Do TJ /Type /XObject >> >> 0 G q 0.564 G /Meta26 39 0 R endobj q Q 0 G /BBox [0 0 534.67 16.44] /F3 17 0 R /Meta341 Do endstream endobj /ProcSet[/PDF] >> (-) Tj BT /Meta120 Do 347 0 obj >> Q /Length 69 /F3 12.131 Tf 0.737 w /Font << 0 g 1.014 0 0 1.006 251.439 763.351 cm /Subtype /Form Q 1.502 5.203 TD 1 i /Length 16 >> /Producer (PDF-XChange 4.0.0186.0000 \(Windows\))
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